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441552250121 is a prime number
BaseRepresentation
bin1100110110011101001…
…00001010010100001001
31120012201112110101100112
412123032210022110021
524213244334000441
6534502445044105
743621035125243
oct6331644122411
91505645411315
10441552250121
11160296808984
12716aab56635
133283b1784a8
141752a995093
15b7447eb4eb
hex66ce90a509

441552250121 has 2 divisors, whose sum is σ = 441552250122. Its totient is φ = 441552250120.

The previous prime is 441552250103. The next prime is 441552250123. The reversal of 441552250121 is 121052255144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 441274561225 + 277688896 = 664285^2 + 16664^2 .

It is a cyclic number.

It is not a de Polignac number, because 441552250121 - 218 = 441551987977 is a prime.

Together with 441552250123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (441552250123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220776125060 + 220776125061.

It is an arithmetic number, because the mean of its divisors is an integer number (220776125061).

Almost surely, 2441552250121 is an apocalyptic number.

It is an amenable number.

441552250121 is a deficient number, since it is larger than the sum of its proper divisors (1).

441552250121 is an equidigital number, since it uses as much as digits as its factorization.

441552250121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16000, while the sum is 32.

The spelling of 441552250121 in words is "four hundred forty-one billion, five hundred fifty-two million, two hundred fifty thousand, one hundred twenty-one".