Base | Representation |
---|---|
bin | 101001000111110111… |
… | …111101000100001101 |
3 | 11012222021101222212101 |
4 | 221013313331010031 |
5 | 1210412303221331 |
6 | 32141302035101 |
7 | 3122133520126 |
oct | 510767750415 |
9 | 135867358771 |
10 | 44155523341 |
11 | 177a9707256 |
12 | 8683718a91 |
13 | 4218c87c07 |
14 | 21cc44704d |
15 | 123672d061 |
hex | a47dfd10d |
44155523341 has 2 divisors, whose sum is σ = 44155523342. Its totient is φ = 44155523340.
The previous prime is 44155523339. The next prime is 44155523371. The reversal of 44155523341 is 14332555144.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43311853225 + 843670116 = 208115^2 + 29046^2 .
It is a cyclic number.
It is not a de Polignac number, because 44155523341 - 21 = 44155523339 is a prime.
Together with 44155523339, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 44155523341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44155523371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22077761670 + 22077761671.
It is an arithmetic number, because the mean of its divisors is an integer number (22077761671).
Almost surely, 244155523341 is an apocalyptic number.
It is an amenable number.
44155523341 is a deficient number, since it is larger than the sum of its proper divisors (1).
44155523341 is an equidigital number, since it uses as much as digits as its factorization.
44155523341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144000, while the sum is 37.
The spelling of 44155523341 in words is "forty-four billion, one hundred fifty-five million, five hundred twenty-three thousand, three hundred forty-one".
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