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441885254053 is a prime number
BaseRepresentation
bin1100110111000100110…
…10011110000110100101
31120020120202001201212111
412123202122132012211
524214440111112203
6534555502321021
743632220454215
oct6334232360645
91506522051774
10441885254053
11160447784741
1271782589171
1332892160639
141755ccba245
15b763b7926d
hex66e269e1a5

441885254053 has 2 divisors, whose sum is σ = 441885254054. Its totient is φ = 441885254052.

The previous prime is 441885254047. The next prime is 441885254059. The reversal of 441885254053 is 350452588144.

It is a balanced prime because it is at equal distance from previous prime (441885254047) and next prime (441885254059).

It can be written as a sum of positive squares in only one way, i.e., 409744652769 + 32140601284 = 640113^2 + 179278^2 .

It is a cyclic number.

It is not a de Polignac number, because 441885254053 - 213 = 441885245861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 441885253988 and 441885254006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (441885254059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220942627026 + 220942627027.

It is an arithmetic number, because the mean of its divisors is an integer number (220942627027).

Almost surely, 2441885254053 is an apocalyptic number.

It is an amenable number.

441885254053 is a deficient number, since it is larger than the sum of its proper divisors (1).

441885254053 is an equidigital number, since it uses as much as digits as its factorization.

441885254053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072000, while the sum is 49.

The spelling of 441885254053 in words is "four hundred forty-one billion, eight hundred eighty-five million, two hundred fifty-four thousand, fifty-three".