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4423132310081 is a prime number
BaseRepresentation
bin100000001011101011100…
…1110101110101001000001
3120122211212200210011211012
41000113113032232221001
51034432033332410311
613223543043530305
7634363225205312
oct100272716565101
916584780704735
104423132310081
111455926972a01
125b5296089995
1326113aa40004
1411411b7d2609
157a0c85eb78b
hex405d73aea41

4423132310081 has 2 divisors, whose sum is σ = 4423132310082. Its totient is φ = 4423132310080.

The previous prime is 4423132310039. The next prime is 4423132310123. The reversal of 4423132310081 is 1800132313244.

It is a balanced prime because it is at equal distance from previous prime (4423132310039) and next prime (4423132310123).

It can be written as a sum of positive squares in only one way, i.e., 2551817748481 + 1871314561600 = 1597441^2 + 1367960^2 .

It is a cyclic number.

It is not a de Polignac number, because 4423132310081 - 26 = 4423132310017 is a prime.

It is a super-2 number, since 2×44231323100812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4423132310021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2211566155040 + 2211566155041.

It is an arithmetic number, because the mean of its divisors is an integer number (2211566155041).

Almost surely, 24423132310081 is an apocalyptic number.

It is an amenable number.

4423132310081 is a deficient number, since it is larger than the sum of its proper divisors (1).

4423132310081 is an equidigital number, since it uses as much as digits as its factorization.

4423132310081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 32.

The spelling of 4423132310081 in words is "four trillion, four hundred twenty-three billion, one hundred thirty-two million, three hundred ten thousand, eighty-one".