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4425242115401 is a prime number
BaseRepresentation
bin100000001100101010011…
…1110111111110101001001
3120200001022201202101121222
41000121110332333311021
51040000343440143101
613224532252211425
7634466424231242
oct100312476776511
916601281671558
104425242115401
111456809898968
125b5784769b75
132613b5b81c23
1411427bab1cc9
157a19d94e01b
hex40654fbfd49

4425242115401 has 2 divisors, whose sum is σ = 4425242115402. Its totient is φ = 4425242115400.

The previous prime is 4425242115397. The next prime is 4425242115403. The reversal of 4425242115401 is 1045112425244.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2881438350400 + 1543803765001 = 1697480^2 + 1242499^2 .

It is a cyclic number.

It is not a de Polignac number, because 4425242115401 - 22 = 4425242115397 is a prime.

Together with 4425242115403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4425242115403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2212621057700 + 2212621057701.

It is an arithmetic number, because the mean of its divisors is an integer number (2212621057701).

Almost surely, 24425242115401 is an apocalyptic number.

It is an amenable number.

4425242115401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4425242115401 is an equidigital number, since it uses as much as digits as its factorization.

4425242115401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51200, while the sum is 35.

The spelling of 4425242115401 in words is "four trillion, four hundred twenty-five billion, two hundred forty-two million, one hundred fifteen thousand, four hundred one".