Search a number
-
+
44312117766701 is a prime number
BaseRepresentation
bin10100001001101001110000…
…00010011110101000101101
312210220012022200021001212212
422010310320002132220231
521302002204122013301
6234124412245140205
712222305405226221
oct1204647002365055
9183805280231785
1044312117766701
11131347332a0464
124b77b9a6ba665
131b957cb87ab45
14ad2a0a072781
1551c9d711a4bb
hex284d3809ea2d

44312117766701 has 2 divisors, whose sum is σ = 44312117766702. Its totient is φ = 44312117766700.

The previous prime is 44312117766661. The next prime is 44312117766727. The reversal of 44312117766701 is 10766771121344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32017094473225 + 12295023293476 = 5658365^2 + 3506426^2 .

It is a cyclic number.

It is not a de Polignac number, because 44312117766701 - 214 = 44312117750317 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 44312117766701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44312117756701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156058883350 + 22156058883351.

It is an arithmetic number, because the mean of its divisors is an integer number (22156058883351).

Almost surely, 244312117766701 is an apocalyptic number.

It is an amenable number.

44312117766701 is a deficient number, since it is larger than the sum of its proper divisors (1).

44312117766701 is an equidigital number, since it uses as much as digits as its factorization.

44312117766701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1185408, while the sum is 50.

The spelling of 44312117766701 in words is "forty-four trillion, three hundred twelve billion, one hundred seventeen million, seven hundred sixty-six thousand, seven hundred one".