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44312117766661 is a prime number
BaseRepresentation
bin10100001001101001110000…
…00010011110101000000101
312210220012022200021001211101
422010310320002132220011
521302002204122013121
6234124412245140101
712222305405226133
oct1204647002365005
9183805280231741
1044312117766661
11131347332a0428
124b77b9a6ba631
131b957cb87ab14
14ad2a0a072753
1551c9d711a491
hex284d3809ea05

44312117766661 has 2 divisors, whose sum is σ = 44312117766662. Its totient is φ = 44312117766660.

The previous prime is 44312117766647. The next prime is 44312117766701. The reversal of 44312117766661 is 16666771121344.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26941352536036 + 17370765230625 = 5190506^2 + 4167825^2 .

It is a cyclic number.

It is not a de Polignac number, because 44312117766661 - 27 = 44312117766533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44312115766661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156058883330 + 22156058883331.

It is an arithmetic number, because the mean of its divisors is an integer number (22156058883331).

Almost surely, 244312117766661 is an apocalyptic number.

It is an amenable number.

44312117766661 is a deficient number, since it is larger than the sum of its proper divisors (1).

44312117766661 is an equidigital number, since it uses as much as digits as its factorization.

44312117766661 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6096384, while the sum is 55.

The spelling of 44312117766661 in words is "forty-four trillion, three hundred twelve billion, one hundred seventeen million, seven hundred sixty-six thousand, six hundred sixty-one".