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4431215132117 is a prime number
BaseRepresentation
bin100000001111011100100…
…0000001111110111010101
3120200121202000001002012022
41000132321000033313111
51040100112033211432
613231401102502525
7635100433104164
oct100367100176725
916617660032168
104431215132117
1114592a4469814
125b6970b94a45
13261b28490b47
141146870993db
157a3ed006b12
hex407b900fdd5

4431215132117 has 2 divisors, whose sum is σ = 4431215132118. Its totient is φ = 4431215132116.

The previous prime is 4431215132107. The next prime is 4431215132129. The reversal of 4431215132117 is 7112315121344.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4413734590321 + 17480541796 = 2100889^2 + 132214^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4431215132117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4431215132107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215607566058 + 2215607566059.

It is an arithmetic number, because the mean of its divisors is an integer number (2215607566059).

Almost surely, 24431215132117 is an apocalyptic number.

It is an amenable number.

4431215132117 is a deficient number, since it is larger than the sum of its proper divisors (1).

4431215132117 is an equidigital number, since it uses as much as digits as its factorization.

4431215132117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 35.

The spelling of 4431215132117 in words is "four trillion, four hundred thirty-one billion, two hundred fifteen million, one hundred thirty-two thousand, one hundred seventeen".