Search a number
-
+
4431215132129 is a prime number
BaseRepresentation
bin100000001111011100100…
…0000001111110111100001
3120200121202000001002012202
41000132321000033313201
51040100112033212004
613231401102502545
7635100433104212
oct100367100176741
916617660032182
104431215132129
1114592a4469825
125b6970b94a55
13261b28490b56
14114687099409
157a3ed006b1e
hex407b900fde1

4431215132129 has 2 divisors, whose sum is σ = 4431215132130. Its totient is φ = 4431215132128.

The previous prime is 4431215132117. The next prime is 4431215132131. The reversal of 4431215132129 is 9212315121344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3620449951504 + 810765180625 = 1902748^2 + 900425^2 .

It is a cyclic number.

It is not a de Polignac number, because 4431215132129 - 28 = 4431215131873 is a prime.

Together with 4431215132131, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4431215132092 and 4431215132101.

It is not a weakly prime, because it can be changed into another prime (4431215332129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215607566064 + 2215607566065.

It is an arithmetic number, because the mean of its divisors is an integer number (2215607566065).

Almost surely, 24431215132129 is an apocalyptic number.

It is an amenable number.

4431215132129 is a deficient number, since it is larger than the sum of its proper divisors (1).

4431215132129 is an equidigital number, since it uses as much as digits as its factorization.

4431215132129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 51840, while the sum is 38.

The spelling of 4431215132129 in words is "four trillion, four hundred thirty-one billion, two hundred fifteen million, one hundred thirty-two thousand, one hundred twenty-nine".