Base | Representation |
---|---|
bin | 100000001111011100101… |
… | …1111111010011110100000 |
3 | 120200121202120122211000212 |
4 | 1000132321133322132200 |
5 | 1040100121144324440 |
6 | 13231402000433252 |
7 | 635100563466311 |
oct | 100367137723640 |
9 | 16617676584025 |
10 | 4431223433120 |
11 | 14592a9119450 |
12 | 5b6973918828 |
13 | 261b2a109293 |
14 | 11468821a608 |
15 | 7a3edae6465 |
hex | 407b97fa7a0 |
4431223433120 has 96 divisors (see below), whose sum is σ = 11699019573696. Its totient is φ = 1572052633600.
The previous prime is 4431223433081. The next prime is 4431223433123. The reversal of 4431223433120 is 213343221344.
It is a super-2 number, since 2×44312234331202 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is not an unprimeable number, because it can be changed into a prime (4431223433123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30631994 + ... + 30776313.
It is an arithmetic number, because the mean of its divisors is an integer number (121864787226).
Almost surely, 24431223433120 is an apocalyptic number.
4431223433120 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
4431223433120 is an abundant number, since it is smaller than the sum of its proper divisors (7267796140576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4431223433120 is a wasteful number, since it uses less digits than its factorization.
4431223433120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61408374 (or 61408366 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 4431223433120 its reverse (213343221344), we get a palindrome (4644566654464).
It can be divided in two parts, 44312 and 23433120, that added together give a palindrome (23477432).
The spelling of 4431223433120 in words is "four trillion, four hundred thirty-one billion, two hundred twenty-three million, four hundred thirty-three thousand, one hundred twenty".
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