Base | Representation |
---|---|
bin | 100000001111011100111… |
… | …1101101000011001101000 |
3 | 120200121210010022121021202 |
4 | 1000132321331220121220 |
5 | 1040100130143122100 |
6 | 13231402435423332 |
7 | 635101016633432 |
oct | 100367175503150 |
9 | 16617703277252 |
10 | 4431231223400 |
11 | 145930255a3a3 |
12 | 5b6976454b48 |
13 | 261b2b906107 |
14 | 114689287652 |
15 | 7a3ee6347d5 |
hex | 407b9f68668 |
4431231223400 has 48 divisors (see below), whose sum is σ = 10908648637740. Its totient is φ = 1668228224000.
The previous prime is 4431231223387. The next prime is 4431231223403. The reversal of 4431231223400 is 43221321344.
It can be written as a sum of positive squares in 6 ways, for example, as 3741524227204 + 689706996196 = 1934302^2 + 830486^2 .
It is not an unprimeable number, because it can be changed into a prime (4431231223403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 651648251 + ... + 651655050.
Almost surely, 24431231223400 is an apocalyptic number.
4431231223400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
4431231223400 is an abundant number, since it is smaller than the sum of its proper divisors (6477417414340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4431231223400 is a wasteful number, since it uses less digits than its factorization.
4431231223400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1303303334 (or 1303303325 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 4431231223400 its reverse (43221321344), we get a palindrome (4474452544744).
The spelling of 4431231223400 in words is "four trillion, four hundred thirty-one billion, two hundred thirty-one million, two hundred twenty-three thousand, four hundred".
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