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44313173117 is a prime number
BaseRepresentation
bin101001010001010001…
…010101110001111101
311020101021001102200222
4221101101111301331
51211223133014432
632205053031125
73126056520353
oct512121256175
9136337042628
1044313173117
111787a6a3924
1287084854a5
1342428349c5
1422053637d3
1512454be112
hexa51455c7d

44313173117 has 2 divisors, whose sum is σ = 44313173118. Its totient is φ = 44313173116.

The previous prime is 44313173089. The next prime is 44313173119. The reversal of 44313173117 is 71137131344.

44313173117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33890600836 + 10422572281 = 184094^2 + 102091^2 .

It is a cyclic number.

It is not a de Polignac number, because 44313173117 - 26 = 44313173053 is a prime.

It is a super-2 number, since 2×443131731172 (a number of 22 digits) contains 22 as substring.

Together with 44313173119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44313173119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156586558 + 22156586559.

It is an arithmetic number, because the mean of its divisors is an integer number (22156586559).

Almost surely, 244313173117 is an apocalyptic number.

It is an amenable number.

44313173117 is a deficient number, since it is larger than the sum of its proper divisors (1).

44313173117 is an equidigital number, since it uses as much as digits as its factorization.

44313173117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21168, while the sum is 35.

The spelling of 44313173117 in words is "forty-four billion, three hundred thirteen million, one hundred seventy-three thousand, one hundred seventeen".