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4440105223241 is a prime number
BaseRepresentation
bin100000010011100101011…
…1001010000010001001001
3120201110200120022111120112
41000213022321100101021
51040221313414120431
613235431200204105
7635533642453202
oct100471271202111
916643616274515
104440105223241
111462046710866
125b8632309635
1326291423b3ac
14114c8ba605a9
157a76d722c2b
hex409cae50449

4440105223241 has 2 divisors, whose sum is σ = 4440105223242. Its totient is φ = 4440105223240.

The previous prime is 4440105223231. The next prime is 4440105223243. The reversal of 4440105223241 is 1423225010444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3427071025225 + 1013034198016 = 1851235^2 + 1006496^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4440105223241 is a prime.

Together with 4440105223243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4440105223198 and 4440105223207.

It is not a weakly prime, because it can be changed into another prime (4440105223243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220052611620 + 2220052611621.

It is an arithmetic number, because the mean of its divisors is an integer number (2220052611621).

Almost surely, 24440105223241 is an apocalyptic number.

It is an amenable number.

4440105223241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4440105223241 is an equidigital number, since it uses as much as digits as its factorization.

4440105223241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30720, while the sum is 32.

The spelling of 4440105223241 in words is "four trillion, four hundred forty billion, one hundred five million, two hundred twenty-three thousand, two hundred forty-one".