Base | Representation |
---|---|
bin | 101001010110100100… |
… | …101110010101010101 |
3 | 11020121110110110000021 |
4 | 221112210232111111 |
5 | 1211413421444001 |
6 | 32221551545141 |
7 | 3131216652445 |
oct | 512644562525 |
9 | 136543413007 |
10 | 44402140501 |
11 | 1791593a394 |
12 | 873222b1b1 |
13 | 42580b4924 |
14 | 22130c2125 |
15 | 124d1e4ba1 |
hex | a5692e555 |
44402140501 has 2 divisors, whose sum is σ = 44402140502. Its totient is φ = 44402140500.
The previous prime is 44402140451. The next prime is 44402140547. The reversal of 44402140501 is 10504120444.
44402140501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27228300100 + 17173840401 = 165010^2 + 131049^2 .
It is a cyclic number.
It is not a de Polignac number, because 44402140501 - 27 = 44402140373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44402140301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22201070250 + 22201070251.
It is an arithmetic number, because the mean of its divisors is an integer number (22201070251).
Almost surely, 244402140501 is an apocalyptic number.
It is an amenable number.
44402140501 is a deficient number, since it is larger than the sum of its proper divisors (1).
44402140501 is an equidigital number, since it uses as much as digits as its factorization.
44402140501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 44402140501 its reverse (10504120444), we get a palindrome (54906260945).
The spelling of 44402140501 in words is "forty-four billion, four hundred two million, one hundred forty thousand, five hundred one".
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