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4442243126117 is a prime number
BaseRepresentation
bin100000010100100101001…
…0100101101001101100101
3120201200012120011012222112
41000221022110231031211
51040240203220013432
613240423251010405
7635640632362166
oct100511224551545
916650176135875
104442243126117
111462a43487945
125b8b2a299a05
13262b9513a394
1411501197576d
157a8462757b2
hex40a4a52d365

4442243126117 has 2 divisors, whose sum is σ = 4442243126118. Its totient is φ = 4442243126116.

The previous prime is 4442243126089. The next prime is 4442243126131. The reversal of 4442243126117 is 7116213422444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2500696286881 + 1941546839236 = 1581359^2 + 1393394^2 .

It is a cyclic number.

It is not a de Polignac number, because 4442243126117 - 26 = 4442243126053 is a prime.

It is a super-3 number, since 3×44422431261173 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4442243126177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2221121563058 + 2221121563059.

It is an arithmetic number, because the mean of its divisors is an integer number (2221121563059).

Almost surely, 24442243126117 is an apocalyptic number.

It is an amenable number.

4442243126117 is a deficient number, since it is larger than the sum of its proper divisors (1).

4442243126117 is an equidigital number, since it uses as much as digits as its factorization.

4442243126117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 258048, while the sum is 41.

The spelling of 4442243126117 in words is "four trillion, four hundred forty-two billion, two hundred forty-three million, one hundred twenty-six thousand, one hundred seventeen".