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4442243126131 is a prime number
BaseRepresentation
bin100000010100100101001…
…0100101101001101110011
3120201200012120011020000001
41000221022110231031303
51040240203220014011
613240423251010431
7635640632362216
oct100511224551563
916650176136001
104442243126131
111462a43487958
125b8b2a299a17
13262b9513a3a5
1411501197577d
157a8462757c1
hex40a4a52d373

4442243126131 has 2 divisors, whose sum is σ = 4442243126132. Its totient is φ = 4442243126130.

The previous prime is 4442243126117. The next prime is 4442243126159. The reversal of 4442243126131 is 1316213422444.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4442243126131 - 215 = 4442243093363 is a prime.

It is a super-3 number, since 3×44422431261313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (4442243126231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2221121563065 + 2221121563066.

It is an arithmetic number, because the mean of its divisors is an integer number (2221121563066).

Almost surely, 24442243126131 is an apocalyptic number.

4442243126131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4442243126131 is an equidigital number, since it uses as much as digits as its factorization.

4442243126131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 110592, while the sum is 37.

Adding to 4442243126131 its reverse (1316213422444), we get a palindrome (5758456548575).

The spelling of 4442243126131 in words is "four trillion, four hundred forty-two billion, two hundred forty-three million, one hundred twenty-six thousand, one hundred thirty-one".