Base | Representation |
---|---|
bin | 101001011001000001… |
… | …110001111111110101 |
3 | 11020201022221011211221 |
4 | 221121001301333311 |
5 | 1212004441441432 |
6 | 32230022230341 |
7 | 3132226630351 |
oct | 513101617765 |
9 | 136638834757 |
10 | 44443312117 |
11 | 17937100216 |
12 | 8743b853b1 |
13 | 426379b829 |
14 | 221875c461 |
15 | 1251b28b97 |
hex | a59071ff5 |
44443312117 has 2 divisors, whose sum is σ = 44443312118. Its totient is φ = 44443312116.
The previous prime is 44443312033. The next prime is 44443312217. The reversal of 44443312117 is 71121334444.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41130273636 + 3313038481 = 202806^2 + 57559^2 .
It is a cyclic number.
It is not a de Polignac number, because 44443312117 - 231 = 42295828469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44443312217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22221656058 + 22221656059.
It is an arithmetic number, because the mean of its divisors is an integer number (22221656059).
Almost surely, 244443312117 is an apocalyptic number.
It is an amenable number.
44443312117 is a deficient number, since it is larger than the sum of its proper divisors (1).
44443312117 is an equidigital number, since it uses as much as digits as its factorization.
44443312117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 32256, while the sum is 34.
The spelling of 44443312117 in words is "forty-four billion, four hundred forty-three million, three hundred twelve thousand, one hundred seventeen".
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