Search a number
-
+
445454047830131 is a prime number
BaseRepresentation
bin110010101001000110101101…
…0010010001110000001110011
32011102012222202111101212112122
41211102031122102032001303
5431341304342221031011
64215222433044344455
7162553664365441154
oct14522153222160163
92142188674355478
10445454047830131
11119a3200104532a
1241b63b8b3a512b
13161731a0a84a82
147c0013b80392b
153677436d7c3db
hex195235a48e073

445454047830131 has 2 divisors, whose sum is σ = 445454047830132. Its totient is φ = 445454047830130.

The previous prime is 445454047830119. The next prime is 445454047830223. The reversal of 445454047830131 is 131038740454544.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 445454047830131 - 230 = 445452974088307 is a prime.

It is a super-2 number, since 2×4454540478301312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (445454047830101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222727023915065 + 222727023915066.

It is an arithmetic number, because the mean of its divisors is an integer number (222727023915066).

Almost surely, 2445454047830131 is an apocalyptic number.

445454047830131 is a deficient number, since it is larger than the sum of its proper divisors (1).

445454047830131 is an equidigital number, since it uses as much as digits as its factorization.

445454047830131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12902400, while the sum is 53.

The spelling of 445454047830131 in words is "four hundred forty-five trillion, four hundred fifty-four billion, forty-seven million, eight hundred thirty thousand, one hundred thirty-one".