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45001933730519 is a prime number
BaseRepresentation
bin10100011101101110101000…
…10001100011001011010111
312220100010212010200211022112
422032313110101203023113
521344302430013334034
6235413334123221235
712323165604202163
oct1216672421431327
9186303763624275
1045001933730519
1113380238435a27
12506981467781b
131c1588317256c
14b181689c9ca3
1553090c0b07ce
hex28edd44632d7

45001933730519 has 2 divisors, whose sum is σ = 45001933730520. Its totient is φ = 45001933730518.

The previous prime is 45001933730491. The next prime is 45001933730521. The reversal of 45001933730519 is 91503733910054.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 45001933730519 - 228 = 45001665295063 is a prime.

It is a super-2 number, since 2×450019337305192 (a number of 28 digits) contains 22 as substring.

Together with 45001933730521, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (45001933730549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22500966865259 + 22500966865260.

It is an arithmetic number, because the mean of its divisors is an integer number (22500966865260).

Almost surely, 245001933730519 is an apocalyptic number.

45001933730519 is a deficient number, since it is larger than the sum of its proper divisors (1).

45001933730519 is an equidigital number, since it uses as much as digits as its factorization.

45001933730519 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1530900, while the sum is 50.

The spelling of 45001933730519 in words is "forty-five trillion, one billion, nine hundred thirty-three million, seven hundred thirty thousand, five hundred nineteen".