Base | Representation |
---|---|
bin | 100000101111100111011… |
… | …0010010001110011101111 |
3 | 120221020001122111022021212 |
4 | 1001133032302101303233 |
5 | 1042213103302424201 |
6 | 13323224224145035 |
7 | 643064426142032 |
oct | 101371662216357 |
9 | 16836048438255 |
10 | 4500300045551 |
11 | 14856260647a2 |
12 | 60823146817b |
13 | 2684b815bc4b |
14 | 117b5c349019 |
15 | 7c0e310aabb |
hex | 417cec91cef |
4500300045551 has 2 divisors, whose sum is σ = 4500300045552. Its totient is φ = 4500300045550.
The previous prime is 4500300045523. The next prime is 4500300045569. The reversal of 4500300045551 is 1555400030054.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4500300045551 is a prime.
It is a super-3 number, since 3×45003000455513 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4500300045511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2250150022775 + 2250150022776.
It is an arithmetic number, because the mean of its divisors is an integer number (2250150022776).
Almost surely, 24500300045551 is an apocalyptic number.
4500300045551 is a deficient number, since it is larger than the sum of its proper divisors (1).
4500300045551 is an equidigital number, since it uses as much as digits as its factorization.
4500300045551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 32.
The spelling of 4500300045551 in words is "four trillion, five hundred billion, three hundred million, forty-five thousand, five hundred fifty-one".
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