Search a number
-
+
4510304011013 is a prime number
BaseRepresentation
bin100000110100010001100…
…0100011000001100000101
3120222011212211201102000012
41001220203010120030011
51042344100311323023
613332001032000005
7643600352351063
oct101504304301405
916864784642005
104510304011013
11148989a038049
1260a163830005
13269420907338
1411842ac21033
157c4cb4ed978
hex41a23118305

4510304011013 has 2 divisors, whose sum is σ = 4510304011014. Its totient is φ = 4510304011012.

The previous prime is 4510304011001. The next prime is 4510304011019. The reversal of 4510304011013 is 3101104030154.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4024685970244 + 485618040769 = 2006162^2 + 696863^2 .

It is a cyclic number.

It is not a de Polignac number, because 4510304011013 - 214 = 4510303994629 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4510304011013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4510304011019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2255152005506 + 2255152005507.

It is an arithmetic number, because the mean of its divisors is an integer number (2255152005507).

Almost surely, 24510304011013 is an apocalyptic number.

It is an amenable number.

4510304011013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4510304011013 is an equidigital number, since it uses as much as digits as its factorization.

4510304011013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 4510304011013 its reverse (3101104030154), we get a palindrome (7611408041167).

The spelling of 4510304011013 in words is "four trillion, five hundred ten billion, three hundred four million, eleven thousand, thirteen".