Base | Representation |
---|---|
bin | 10100100000111100111110… |
… | …01010000011000011000111 |
3 | 12220201201210110000211012202 |
4 | 22100132133022003003013 |
5 | 21403111313200034114 |
6 | 235540254344105115 |
7 | 12334200023451005 |
oct | 1220363712030307 |
9 | 186651713024182 |
10 | 45112711721159 |
11 | 13413214753a05 |
12 | 508718ba6519b |
13 | 1c231588b7454 |
14 | b1d677249a75 |
15 | 533742633cde |
hex | 29079f2830c7 |
45112711721159 has 2 divisors, whose sum is σ = 45112711721160. Its totient is φ = 45112711721158.
The previous prime is 45112711721131. The next prime is 45112711721167. The reversal of 45112711721159 is 95112711721154.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-45112711721159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45112711721179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22556355860579 + 22556355860580.
It is an arithmetic number, because the mean of its divisors is an integer number (22556355860580).
Almost surely, 245112711721159 is an apocalyptic number.
45112711721159 is a deficient number, since it is larger than the sum of its proper divisors (1).
45112711721159 is an equidigital number, since it uses as much as digits as its factorization.
45112711721159 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 176400, while the sum is 47.
The spelling of 45112711721159 in words is "forty-five trillion, one hundred twelve billion, seven hundred eleven million, seven hundred twenty-one thousand, one hundred fifty-nine".
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