Base | Representation |
---|---|
bin | 10100101101101101110010… |
… | …00100110010101111100111 |
3 | 12222021122200202120212011211 |
4 | 22112312321010302233213 |
5 | 21432302411200343323 |
6 | 240513540405412251 |
7 | 12410653010606413 |
oct | 1226667104625747 |
9 | 188248622525154 |
10 | 45551233215463 |
11 | 135721956a5108 |
12 | 5138173a0a087 |
13 | 1c55602ba03b1 |
14 | b369974add43 |
15 | 53ed5ad1370d |
hex | 296db9132be7 |
45551233215463 has 2 divisors, whose sum is σ = 45551233215464. Its totient is φ = 45551233215462.
The previous prime is 45551233215461. The next prime is 45551233215619. The reversal of 45551233215463 is 36451233215554.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 45551233215463 - 21 = 45551233215461 is a prime.
Together with 45551233215461, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45551233215461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22775616607731 + 22775616607732.
It is an arithmetic number, because the mean of its divisors is an integer number (22775616607732).
Almost surely, 245551233215463 is an apocalyptic number.
45551233215463 is a deficient number, since it is larger than the sum of its proper divisors (1).
45551233215463 is an equidigital number, since it uses as much as digits as its factorization.
45551233215463 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480000, while the sum is 49.
Subtracting from 45551233215463 its reverse (36451233215554), we obtain a palindrome (9099999999909).
The spelling of 45551233215463 in words is "forty-five trillion, five hundred fifty-one billion, two hundred thirty-three million, two hundred fifteen thousand, four hundred sixty-three".
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