Base | Representation |
---|---|
bin | 101010011011001110… |
… | …111011011101110111 |
3 | 11100120201222202200101 |
4 | 222123032323131313 |
5 | 1221243314230111 |
6 | 32532141254531 |
7 | 3201605036032 |
oct | 523316733567 |
9 | 140521882611 |
10 | 45554055031 |
11 | 18357092871 |
12 | 89b3b64447 |
13 | 43ac941264 |
14 | 22c2096019 |
15 | 12b93d2bc1 |
hex | a9b3bb777 |
45554055031 has 2 divisors, whose sum is σ = 45554055032. Its totient is φ = 45554055030.
The previous prime is 45554055013. The next prime is 45554055059. The reversal of 45554055031 is 13055045554.
It is a happy number.
Together with previous prime (45554055013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 45554055031 - 25 = 45554054999 is a prime.
It is a super-2 number, since 2×455540550312 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (45554055331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22777027515 + 22777027516.
It is an arithmetic number, because the mean of its divisors is an integer number (22777027516).
Almost surely, 245554055031 is an apocalyptic number.
45554055031 is a deficient number, since it is larger than the sum of its proper divisors (1).
45554055031 is an equidigital number, since it uses as much as digits as its factorization.
45554055031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150000, while the sum is 37.
The spelling of 45554055031 in words is "forty-five billion, five hundred fifty-four million, fifty-five thousand, thirty-one".
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