Base | Representation |
---|---|
bin | 101010101010000001… |
… | …010011110110011011 |
3 | 11101020000210221120112 |
4 | 222222001103312123 |
5 | 1222300322040011 |
6 | 33012522514535 |
7 | 3211006535663 |
oct | 525201236633 |
9 | 141200727515 |
10 | 45802143131 |
11 | 18474130058 |
12 | 8a63065a4b |
13 | 441c164654 |
14 | 2306dd51a3 |
15 | 12d108a58b |
hex | aaa053d9b |
45802143131 has 2 divisors, whose sum is σ = 45802143132. Its totient is φ = 45802143130.
The previous prime is 45802143091. The next prime is 45802143133. The reversal of 45802143131 is 13134120854.
45802143131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 45802143131 - 222 = 45797948827 is a prime.
It is a super-2 number, since 2×458021431312 (a number of 22 digits) contains 22 as substring.
Together with 45802143133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (45802143133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22901071565 + 22901071566.
It is an arithmetic number, because the mean of its divisors is an integer number (22901071566).
Almost surely, 245802143131 is an apocalyptic number.
45802143131 is a deficient number, since it is larger than the sum of its proper divisors (1).
45802143131 is an equidigital number, since it uses as much as digits as its factorization.
45802143131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 45802143131 its reverse (13134120854), we get a palindrome (58936263985).
The spelling of 45802143131 in words is "forty-five billion, eight hundred two million, one hundred forty-three thousand, one hundred thirty-one".
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