Base | Representation |
---|---|
bin | 100001111001000111011… |
… | …1010110110101110000001 |
3 | 121111022110221121202111002 |
4 | 1003302032322312232001 |
5 | 1102304333414421032 |
6 | 13523530540301345 |
7 | 660353052420263 |
oct | 103621672665601 |
9 | 17438427552432 |
10 | 4658142342017 |
11 | 1536563a0729a |
12 | 632942541855 |
13 | 27a3513860c8 |
14 | 121653471b33 |
15 | 81280433862 |
hex | 43c8eeb6b81 |
4658142342017 has 2 divisors, whose sum is σ = 4658142342018. Its totient is φ = 4658142342016.
The previous prime is 4658142341981. The next prime is 4658142342019. The reversal of 4658142342017 is 7102432418564.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4576172361601 + 81969980416 = 2139199^2 + 286304^2 .
It is a cyclic number.
It is not a de Polignac number, because 4658142342017 - 212 = 4658142337921 is a prime.
Together with 4658142342019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4658142342019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2329071171008 + 2329071171009.
It is an arithmetic number, because the mean of its divisors is an integer number (2329071171009).
Almost surely, 24658142342017 is an apocalyptic number.
It is an amenable number.
4658142342017 is a deficient number, since it is larger than the sum of its proper divisors (1).
4658142342017 is an equidigital number, since it uses as much as digits as its factorization.
4658142342017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1290240, while the sum is 47.
The spelling of 4658142342017 in words is "four trillion, six hundred fifty-eight billion, one hundred forty-two million, three hundred forty-two thousand, seventeen".
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