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46638314949221 is a prime number
BaseRepresentation
bin10101001101010110101000…
…01100100000101001100101
320010010120122100122201002022
422212223110030200221211
522103110232111333341
6243105202431552525
712552335631103232
oct1246532414405145
9203116570581068
1046638314949221
111395121aa26506
12529299938b745
132003c884c3238
14b73441006789
1555d282609e4b
hex2a6ad4320a65

46638314949221 has 2 divisors, whose sum is σ = 46638314949222. Its totient is φ = 46638314949220.

The previous prime is 46638314949179. The next prime is 46638314949223. The reversal of 46638314949221 is 12294941383664.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44274451749025 + 2363863200196 = 6653905^2 + 1537486^2 .

It is a cyclic number.

It is not a de Polignac number, because 46638314949221 - 26 = 46638314949157 is a prime.

It is a super-3 number, since 3×466383149492213 (a number of 42 digits) contains 333 as substring.

Together with 46638314949223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (46638314949223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23319157474610 + 23319157474611.

It is an arithmetic number, because the mean of its divisors is an integer number (23319157474611).

Almost surely, 246638314949221 is an apocalyptic number.

It is an amenable number.

46638314949221 is a deficient number, since it is larger than the sum of its proper divisors (1).

46638314949221 is an equidigital number, since it uses as much as digits as its factorization.

46638314949221 is an evil number, because the sum of its binary digits is even.

The product of its digits is 53747712, while the sum is 62.

The spelling of 46638314949221 in words is "forty-six trillion, six hundred thirty-eight billion, three hundred fourteen million, nine hundred forty-nine thousand, two hundred twenty-one".