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47183850064361 is a prime number
BaseRepresentation
bin10101011101001110110001…
…00111110100100111101001
320012001201202122012221100202
422232213120213310213221
522141030011104024421
6244203543402441545
712636630535056413
oct1256473047644751
9205051678187322
1047183850064361
111404161630a96a
125360667b032b5
13204355838050a
14b919d39919b3
1556c560b2e10b
hex2ae9d89f49e9

47183850064361 has 2 divisors, whose sum is σ = 47183850064362. Its totient is φ = 47183850064360.

The previous prime is 47183850064339. The next prime is 47183850064363. The reversal of 47183850064361 is 16346005838174.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47104131930025 + 79718134336 = 6863245^2 + 282344^2 .

It is a cyclic number.

It is not a de Polignac number, because 47183850064361 - 26 = 47183850064297 is a prime.

Together with 47183850064363, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 47183850064297 and 47183850064306.

It is not a weakly prime, because it can be changed into another prime (47183850064363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23591925032180 + 23591925032181.

It is an arithmetic number, because the mean of its divisors is an integer number (23591925032181).

Almost surely, 247183850064361 is an apocalyptic number.

It is an amenable number.

47183850064361 is a deficient number, since it is larger than the sum of its proper divisors (1).

47183850064361 is an equidigital number, since it uses as much as digits as its factorization.

47183850064361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11612160, while the sum is 56.

The spelling of 47183850064361 in words is "forty-seven trillion, one hundred eighty-three billion, eight hundred fifty million, sixty-four thousand, three hundred sixty-one".