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47241444221 is a prime number
BaseRepresentation
bin101011111111110011…
…110011101101111101
311111221100010000111022
4223333303303231331
51233222302203341
633411420033525
73261454436036
oct537763635575
9144840100438
1047241444221
1119042622294
1291a50928a5
1345bb3c37ba
142402217a8d
1513675e4e4b
hexaffcf3b7d

47241444221 has 2 divisors, whose sum is σ = 47241444222. Its totient is φ = 47241444220.

The previous prime is 47241444209. The next prime is 47241444223. The reversal of 47241444221 is 12244414274.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45520356025 + 1721088196 = 213355^2 + 41486^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-47241444221 is a prime.

Together with 47241444223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (47241444223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23620722110 + 23620722111.

It is an arithmetic number, because the mean of its divisors is an integer number (23620722111).

Almost surely, 247241444221 is an apocalyptic number.

It is an amenable number.

47241444221 is a deficient number, since it is larger than the sum of its proper divisors (1).

47241444221 is an equidigital number, since it uses as much as digits as its factorization.

47241444221 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 57344, while the sum is 35.

Adding to 47241444221 its reverse (12244414274), we get a palindrome (59485858495).

The spelling of 47241444221 in words is "forty-seven billion, two hundred forty-one million, four hundred forty-four thousand, two hundred twenty-one".