Base | Representation |
---|---|
bin | 110101101101010111110001… |
… | …0010110100000011011100111 |
3 | 2021221201202010010222020102001 |
4 | 1223122233202112200123213 |
5 | 443410233012132234333 |
6 | 4352434432114030131 |
7 | 201336564135540115 |
oct | 15332574226403347 |
9 | 2257652103866361 |
10 | 472428725274343 |
11 | 127591996253752 |
12 | 44b9ba28278347 |
13 | 1737bab73932b6 |
14 | 849395ab48ab5 |
15 | 3993e4e277b7d |
hex | 1adabe25a06e7 |
472428725274343 has 2 divisors, whose sum is σ = 472428725274344. Its totient is φ = 472428725274342.
The previous prime is 472428725274293. The next prime is 472428725274379. The reversal of 472428725274343 is 343472527824274.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 472428725274343 - 245 = 437244353185511 is a prime.
It is a super-2 number, since 2×4724287252743432 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (472428725274943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 236214362637171 + 236214362637172.
It is an arithmetic number, because the mean of its divisors is an integer number (236214362637172).
Almost surely, 2472428725274343 is an apocalyptic number.
472428725274343 is a deficient number, since it is larger than the sum of its proper divisors (1).
472428725274343 is an equidigital number, since it uses as much as digits as its factorization.
472428725274343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 505774080, while the sum is 64.
The spelling of 472428725274343 in words is "four hundred seventy-two trillion, four hundred twenty-eight billion, seven hundred twenty-five million, two hundred seventy-four thousand, three hundred forty-three".
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