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472503147486053 is a prime number
BaseRepresentation
bin110101101101111010011011…
…0010000101101101101100101
32021221222212012202111022022112
41223123310312100231231211
5443412442421224023203
64352532541020210405
7201345140321105225
oct15333646620555545
92257885182438275
10472503147486053
11127610506695942
1244bb2338099a05
1317385b17a49968
1484973babbc085
153995d57c0d6d8
hex1adbd3642db65

472503147486053 has 2 divisors, whose sum is σ = 472503147486054. Its totient is φ = 472503147486052.

The previous prime is 472503147486043. The next prime is 472503147486077. The reversal of 472503147486053 is 350684741305274.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 357585755163844 + 114917392322209 = 18909938^2 + 10719953^2 .

It is a cyclic number.

It is not a de Polignac number, because 472503147486053 - 240 = 471403635858277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 472503147485983 and 472503147486001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (472503147486043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 236251573743026 + 236251573743027.

It is an arithmetic number, because the mean of its divisors is an integer number (236251573743027).

Almost surely, 2472503147486053 is an apocalyptic number.

It is an amenable number.

472503147486053 is a deficient number, since it is larger than the sum of its proper divisors (1).

472503147486053 is an equidigital number, since it uses as much as digits as its factorization.

472503147486053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67737600, while the sum is 59.

The spelling of 472503147486053 in words is "four hundred seventy-two trillion, five hundred three billion, one hundred forty-seven million, four hundred eighty-six thousand, fifty-three".