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47365504973 is a prime number
BaseRepresentation
bin101100000111001101…
…000011111111001101
311112020222112221211222
4230013031003333031
51234001032124343
633432011053125
73264522102143
oct540715037715
9145228487758
1047365504973
11190a6657a36
12921a7411a5
13460b00cb27
1424148ad593
15137344da68
hexb07343fcd

47365504973 has 2 divisors, whose sum is σ = 47365504974. Its totient is φ = 47365504972.

The previous prime is 47365504943. The next prime is 47365505017. The reversal of 47365504973 is 37940556374.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25484291044 + 21881213929 = 159638^2 + 147923^2 .

It is a cyclic number.

It is not a de Polignac number, because 47365504973 - 216 = 47365439437 is a prime.

It is a super-2 number, since 2×473655049732 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (47365504943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23682752486 + 23682752487.

It is an arithmetic number, because the mean of its divisors is an integer number (23682752487).

Almost surely, 247365504973 is an apocalyptic number.

It is an amenable number.

47365504973 is a deficient number, since it is larger than the sum of its proper divisors (1).

47365504973 is an equidigital number, since it uses as much as digits as its factorization.

47365504973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9525600, while the sum is 53.

The spelling of 47365504973 in words is "forty-seven billion, three hundred sixty-five million, five hundred four thousand, nine hundred seventy-three".