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47401367681 is a prime number
BaseRepresentation
bin101100001001010101…
…110111100010000001
311112100111000222020102
4230021111313202001
51234034222231211
633435331452145
73265435656143
oct541125674201
9145314028212
1047401367681
1119114922138
12922a757055
134615588475
142419566c93
151376684a3b
hexb09577881

47401367681 has 2 divisors, whose sum is σ = 47401367682. Its totient is φ = 47401367680.

The previous prime is 47401367677. The next prime is 47401367683. The reversal of 47401367681 is 18676310474.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47255803456 + 145564225 = 217384^2 + 12065^2 .

It is a cyclic number.

It is not a de Polignac number, because 47401367681 - 22 = 47401367677 is a prime.

It is a super-3 number, since 3×474013676813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 47401367683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (47401367683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23700683840 + 23700683841.

It is an arithmetic number, because the mean of its divisors is an integer number (23700683841).

Almost surely, 247401367681 is an apocalyptic number.

It is an amenable number.

47401367681 is a deficient number, since it is larger than the sum of its proper divisors (1).

47401367681 is an equidigital number, since it uses as much as digits as its factorization.

47401367681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 677376, while the sum is 47.

The spelling of 47401367681 in words is "forty-seven billion, four hundred one million, three hundred sixty-seven thousand, six hundred eighty-one".