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475113437 is a prime number
BaseRepresentation
bin11100010100011…
…010011111011101
31020010000021002222
4130110122133131
51433112112222
6115051155125
714526253241
oct3424323735
91203007088
10475113437
11224209837
12113145aa5
1377580716
1447158421
152ba9e542
hex1c51a7dd

475113437 has 2 divisors, whose sum is σ = 475113438. Its totient is φ = 475113436.

The previous prime is 475113427. The next prime is 475113439. The reversal of 475113437 is 734311574.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 254115481 + 220997956 = 15941^2 + 14866^2 .

It is a cyclic number.

It is not a de Polignac number, because 475113437 - 24 = 475113421 is a prime.

It is a super-3 number, since 3×4751134373 (a number of 27 digits) contains 333 as substring.

Together with 475113439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 475113397 and 475113406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (475113439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 237556718 + 237556719.

It is an arithmetic number, because the mean of its divisors is an integer number (237556719).

Almost surely, 2475113437 is an apocalyptic number.

It is an amenable number.

475113437 is a deficient number, since it is larger than the sum of its proper divisors (1).

475113437 is an equidigital number, since it uses as much as digits as its factorization.

475113437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 35280, while the sum is 35.

The square root of 475113437 is about 21797.0969856080. The cubic root of 475113437 is about 780.3074817749.

The spelling of 475113437 in words is "four hundred seventy-five million, one hundred thirteen thousand, four hundred thirty-seven".