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4780344922253 is a prime number
BaseRepresentation
bin100010110010000001011…
…0000101101000010001101
3121220222220110100001001022
41011210002300231002031
51111310121300003003
614100020553523525
71002240255256355
oct105440260550215
917828813301038
104780344922253
1115833730a355a
12652567a135a5
13288a27996394
14127527127b65
1584533965738
hex45902c2d08d

4780344922253 has 2 divisors, whose sum is σ = 4780344922254. Its totient is φ = 4780344922252.

The previous prime is 4780344922247. The next prime is 4780344922267. The reversal of 4780344922253 is 3522294430874.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4697505721129 + 82839201124 = 2167373^2 + 287818^2 .

It is a cyclic number.

It is not a de Polignac number, because 4780344922253 - 26 = 4780344922189 is a prime.

It is a super-2 number, since 2×47803449222532 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4780344922195 and 4780344922204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4780344922753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2390172461126 + 2390172461127.

It is an arithmetic number, because the mean of its divisors is an integer number (2390172461127).

Almost surely, 24780344922253 is an apocalyptic number.

It is an amenable number.

4780344922253 is a deficient number, since it is larger than the sum of its proper divisors (1).

4780344922253 is an equidigital number, since it uses as much as digits as its factorization.

4780344922253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11612160, while the sum is 53.

The spelling of 4780344922253 in words is "four trillion, seven hundred eighty billion, three hundred forty-four million, nine hundred twenty-two thousand, two hundred fifty-three".