Base | Representation |
---|---|
bin | 101100110010010111… |
… | …010100010000100011 |
3 | 11121010110002110210122 |
4 | 230302113110100203 |
5 | 1241441420111342 |
6 | 34031515150455 |
7 | 3321463653236 |
oct | 546227242043 |
9 | 147113073718 |
10 | 48089613347 |
11 | 19438373306 |
12 | 93a114542b |
13 | 46c5040619 |
14 | 2482b2141d |
15 | 13b6cd44d2 |
hex | b325d4423 |
48089613347 has 2 divisors, whose sum is σ = 48089613348. Its totient is φ = 48089613346.
The previous prime is 48089613293. The next prime is 48089613349. The reversal of 48089613347 is 74331698084.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48089613347 - 210 = 48089612323 is a prime.
It is a super-3 number, since 3×480896133473 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 48089613349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (48089613349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24044806673 + 24044806674.
It is an arithmetic number, because the mean of its divisors is an integer number (24044806674).
Almost surely, 248089613347 is an apocalyptic number.
48089613347 is a deficient number, since it is larger than the sum of its proper divisors (1).
48089613347 is an equidigital number, since it uses as much as digits as its factorization.
48089613347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3483648, while the sum is 53.
The spelling of 48089613347 in words is "forty-eight billion, eighty-nine million, six hundred thirteen thousand, three hundred forty-seven".
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