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4825635211213 is a prime number
BaseRepresentation
bin100011000111000111001…
…0001011100011111001101
3122002022210211000002200221
41012032032101130133031
51113030400103224323
614132511033551341
71005432511340215
oct106161621343715
918068724002627
104825635211213
1115a05a42aaa33
1265b2a7575551
13290094a8512b
141297c215d245
15857d4ae555d
hex4638e45c7cd

4825635211213 has 2 divisors, whose sum is σ = 4825635211214. Its totient is φ = 4825635211212.

The previous prime is 4825635211211. The next prime is 4825635211301. The reversal of 4825635211213 is 3121125365284.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3721492399689 + 1104142811524 = 1929117^2 + 1050782^2 .

It is a cyclic number.

It is not a de Polignac number, because 4825635211213 - 21 = 4825635211211 is a prime.

Together with 4825635211211, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 4825635211213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4825635211211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2412817605606 + 2412817605607.

It is an arithmetic number, because the mean of its divisors is an integer number (2412817605607).

Almost surely, 24825635211213 is an apocalyptic number.

It is an amenable number.

4825635211213 is a deficient number, since it is larger than the sum of its proper divisors (1).

4825635211213 is an equidigital number, since it uses as much as digits as its factorization.

4825635211213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 345600, while the sum is 43.

The spelling of 4825635211213 in words is "four trillion, eight hundred twenty-five billion, six hundred thirty-five million, two hundred eleven thousand, two hundred thirteen".