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4830519413 is a prime number
BaseRepresentation
bin1000111111110101…
…11110000001110101
3110110122110210220102
410133322332001311
534343103110123
62115154443445
7230463510656
oct43772760165
913418423812
104830519413
11205977a805
12b29893585
135bc9cbb15
1433b78552d
151d412a028
hex11febe075

4830519413 has 2 divisors, whose sum is σ = 4830519414. Its totient is φ = 4830519412.

The previous prime is 4830519403. The next prime is 4830519439. The reversal of 4830519413 is 3149150384.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3002272849 + 1828246564 = 54793^2 + 42758^2 .

It is a cyclic number.

It is not a de Polignac number, because 4830519413 - 28 = 4830519157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4830519403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2415259706 + 2415259707.

It is an arithmetic number, because the mean of its divisors is an integer number (2415259707).

Almost surely, 24830519413 is an apocalyptic number.

It is an amenable number.

4830519413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4830519413 is an equidigital number, since it uses as much as digits as its factorization.

4830519413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 38.

The square root of 4830519413 is about 69501.9381959957. The cubic root of 4830519413 is about 1690.4329286630.

Adding to 4830519413 its reverse (3149150384), we get a palindrome (7979669797).

The spelling of 4830519413 in words is "four billion, eight hundred thirty million, five hundred nineteen thousand, four hundred thirteen".