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483125333 is a prime number
BaseRepresentation
bin11100110010111…
…110100001010101
31020200002022100212
4130302332201111
51442140002313
6115535015205
714654332445
oct3462764125
91220068325
10483125333
11228791239
1211596a505
13791273a2
1448242125
152c6333a8
hex1ccbe855

483125333 has 2 divisors, whose sum is σ = 483125334. Its totient is φ = 483125332.

The previous prime is 483125303. The next prime is 483125353. The reversal of 483125333 is 333521384.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 363397969 + 119727364 = 19063^2 + 10942^2 .

It is a cyclic number.

It is not a de Polignac number, because 483125333 - 28 = 483125077 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 483125333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (483125303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241562666 + 241562667.

It is an arithmetic number, because the mean of its divisors is an integer number (241562667).

Almost surely, 2483125333 is an apocalyptic number.

It is an amenable number.

483125333 is a deficient number, since it is larger than the sum of its proper divisors (1).

483125333 is an equidigital number, since it uses as much as digits as its factorization.

483125333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25920, while the sum is 32.

The square root of 483125333 is about 21980.1122153641. The cubic root of 483125333 is about 784.6691956807.

The spelling of 483125333 in words is "four hundred eighty-three million, one hundred twenty-five thousand, three hundred thirty-three".