Search a number
-
+
4831734797 is a prime number
BaseRepresentation
bin1000111111111111…
…00110110000001101
3110110201202120002122
410133333212300031
534343411003142
62115240502325
7230510032241
oct43777466015
913421676078
104831734797
11205a42a95a
12b2a17a9a5
135c0036096
1433b9c0421
151d42ba1d2
hex11ffe6c0d

4831734797 has 2 divisors, whose sum is σ = 4831734798. Its totient is φ = 4831734796.

The previous prime is 4831734793. The next prime is 4831734833. The reversal of 4831734797 is 7974371384.

4831734797 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4828999081 + 2735716 = 69491^2 + 1654^2 .

It is a cyclic number.

It is not a de Polignac number, because 4831734797 - 22 = 4831734793 is a prime.

It is a super-2 number, since 2×48317347972 = 46691322297081262418, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4831734793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2415867398 + 2415867399.

It is an arithmetic number, because the mean of its divisors is an integer number (2415867399).

Almost surely, 24831734797 is an apocalyptic number.

It is an amenable number.

4831734797 is a deficient number, since it is larger than the sum of its proper divisors (1).

4831734797 is an equidigital number, since it uses as much as digits as its factorization.

4831734797 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3556224, while the sum is 53.

The square root of 4831734797 is about 69510.6811720328. The cubic root of 4831734797 is about 1690.5746907023.

The spelling of 4831734797 in words is "four billion, eight hundred thirty-one million, seven hundred thirty-four thousand, seven hundred ninety-seven".