Base | Representation |
---|---|
bin | 1110000100000111110… |
… | …01001010101011101101 |
3 | 1201012100110111202222112 |
4 | 13002003321022223231 |
5 | 30404143234412123 |
6 | 1010000202053405 |
7 | 46625235621236 |
oct | 7020371125355 |
9 | 1635313452875 |
10 | 483249138413 |
11 | 176a435a4238 |
12 | 797a71aa265 |
13 | 36754957b62 |
14 | 1956467808d |
15 | c88526ed78 |
hex | 7083e4aaed |
483249138413 has 2 divisors, whose sum is σ = 483249138414. Its totient is φ = 483249138412.
The previous prime is 483249138347. The next prime is 483249138479. The reversal of 483249138413 is 314831942384.
It is a balanced prime because it is at equal distance from previous prime (483249138347) and next prime (483249138479).
It can be written as a sum of positive squares in only one way, i.e., 425851520329 + 57397618084 = 652573^2 + 239578^2 .
It is a cyclic number.
It is not a de Polignac number, because 483249138413 - 212 = 483249134317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (483249138013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241624569206 + 241624569207.
It is an arithmetic number, because the mean of its divisors is an integer number (241624569207).
Almost surely, 2483249138413 is an apocalyptic number.
It is an amenable number.
483249138413 is a deficient number, since it is larger than the sum of its proper divisors (1).
483249138413 is an equidigital number, since it uses as much as digits as its factorization.
483249138413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1990656, while the sum is 50.
The spelling of 483249138413 in words is "four hundred eighty-three billion, two hundred forty-nine million, one hundred thirty-eight thousand, four hundred thirteen".
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