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484124672513039 is a prime number
BaseRepresentation
bin110111000010011110000111…
…1001000011101010000001111
32100111010212101211010201002212
41232010330033020131100033
51001423344312130404124
64433351445414141035
7203654565460665365
oct15604741710352017
92314125354121085
10484124672513039
11130291136590748
124636a73135177b
1317a199b741b66c
148779a8b259635
153ae82d8ce140e
hex1b84f0f21d40f

484124672513039 has 2 divisors, whose sum is σ = 484124672513040. Its totient is φ = 484124672513038.

The previous prime is 484124672512973. The next prime is 484124672513093. The reversal of 484124672513039 is 930315276421484.

It is a happy number.

Together with next prime (484124672513093) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 484124672513039 - 28 = 484124672512783 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (484124672513239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242062336256519 + 242062336256520.

It is an arithmetic number, because the mean of its divisors is an integer number (242062336256520).

It is a 1-persistent number, because it is pandigital, but 2⋅484124672513039 = 968249345026078 is not.

Almost surely, 2484124672513039 is an apocalyptic number.

484124672513039 is a deficient number, since it is larger than the sum of its proper divisors (1).

484124672513039 is an equidigital number, since it uses as much as digits as its factorization.

484124672513039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34836480, while the sum is 59.

The spelling of 484124672513039 in words is "four hundred eighty-four trillion, one hundred twenty-four billion, six hundred seventy-two million, five hundred thirteen thousand, thirty-nine".