Base | Representation |
---|---|
bin | 100011001111100100010… |
… | …1010111010101001010101 |
3 | 122011001200101112121211201 |
4 | 1012133020222322221111 |
5 | 1113330042434223203 |
6 | 14145113021432501 |
7 | 1006644515526655 |
oct | 106371052725125 |
9 | 18131611477751 |
10 | 4843794836053 |
11 | 15a82729a8948 |
12 | 66291510b731 |
13 | 2919ca0a4484 |
14 | 12a625c5c365 |
15 | 85ee8ecee1d |
hex | 467c8abaa55 |
4843794836053 has 2 divisors, whose sum is σ = 4843794836054. Its totient is φ = 4843794836052.
The previous prime is 4843794836011. The next prime is 4843794836129. The reversal of 4843794836053 is 3506384973484.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4336027429969 + 507767406084 = 2082313^2 + 712578^2 .
It is a cyclic number.
It is not a de Polignac number, because 4843794836053 - 221 = 4843792738901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4843792836053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2421897418026 + 2421897418027.
It is an arithmetic number, because the mean of its divisors is an integer number (2421897418027).
Almost surely, 24843794836053 is an apocalyptic number.
It is an amenable number.
4843794836053 is a deficient number, since it is larger than the sum of its proper divisors (1).
4843794836053 is an equidigital number, since it uses as much as digits as its factorization.
4843794836053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209018880, while the sum is 64.
The spelling of 4843794836053 in words is "four trillion, eight hundred forty-three billion, seven hundred ninety-four million, eight hundred thirty-six thousand, fifty-three".
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