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484957267023611 is a prime number
BaseRepresentation
bin110111001000100001110100…
…1101000011101011011111011
32100121002110110202121010212202
41232101003221220131123323
51002031014440324223421
64435230143132100415
7204102002110365134
oct15621035150353373
92317073422533782
10484957267023611
11130582249474688
1246483b7360470b
1317a7a374130585
1487a80b243cc8b
153b0ecb88a610b
hex1b910e9a1d6fb

484957267023611 has 2 divisors, whose sum is σ = 484957267023612. Its totient is φ = 484957267023610.

The previous prime is 484957267023521. The next prime is 484957267023613. The reversal of 484957267023611 is 116320762759484.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 484957267023611 - 210 = 484957267022587 is a prime.

Together with 484957267023613, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (484957267023613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242478633511805 + 242478633511806.

It is an arithmetic number, because the mean of its divisors is an integer number (242478633511806).

It is a 1-persistent number, because it is pandigital, but 2⋅484957267023611 = 969914534047222 is not.

Almost surely, 2484957267023611 is an apocalyptic number.

484957267023611 is a deficient number, since it is larger than the sum of its proper divisors (1).

484957267023611 is an equidigital number, since it uses as much as digits as its factorization.

484957267023611 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 121927680, while the sum is 65.

The spelling of 484957267023611 in words is "four hundred eighty-four trillion, nine hundred fifty-seven billion, two hundred sixty-seven million, twenty-three thousand, six hundred eleven".