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485141456184101 is a prime number
BaseRepresentation
bin110111001001110111100110…
…0001010010110001100100101
32100121202001220012222221222122
41232103233030022112030211
51002042024200240342401
64435450524101035325
7204121212354412133
oct15623571412261445
92317661805887878
10485141456184101
1113064337744a072
12464b37b80b5b45
1317a91848926ac2
1487b2d8674c753
153b14998c4c21b
hex1b93bcc296325

485141456184101 has 2 divisors, whose sum is σ = 485141456184102. Its totient is φ = 485141456184100.

The previous prime is 485141456184097. The next prime is 485141456184139. The reversal of 485141456184101 is 101481654141584.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 456420538728001 + 28720917456100 = 21364001^2 + 5359190^2 .

It is a cyclic number.

It is not a de Polignac number, because 485141456184101 - 22 = 485141456184097 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (485141456184601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242570728092050 + 242570728092051.

It is an arithmetic number, because the mean of its divisors is an integer number (242570728092051).

Almost surely, 2485141456184101 is an apocalyptic number.

It is an amenable number.

485141456184101 is a deficient number, since it is larger than the sum of its proper divisors (1).

485141456184101 is an equidigital number, since it uses as much as digits as its factorization.

485141456184101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2457600, while the sum is 53.

The spelling of 485141456184101 in words is "four hundred eighty-five trillion, one hundred forty-one billion, four hundred fifty-six million, one hundred eighty-four thousand, one hundred one".