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48614929117 is a prime number
BaseRepresentation
bin101101010001101011…
…001111001011011101
311122111001120021120021
4231101223033023131
51244030410212432
634200002352141
73340503036136
oct552153171335
9148431507507
1048614929117
1119687950877
12950905b651
134779b1a561
1424d27c6c8d
1513e7e9d697
hexb51acf2dd

48614929117 has 2 divisors, whose sum is σ = 48614929118. Its totient is φ = 48614929116.

The previous prime is 48614929093. The next prime is 48614929141. The reversal of 48614929117 is 71192941684.

It is a balanced prime because it is at equal distance from previous prime (48614929093) and next prime (48614929141).

It can be written as a sum of positive squares in only one way, i.e., 41868935161 + 6745993956 = 204619^2 + 82134^2 .

It is a cyclic number.

It is not a de Polignac number, because 48614929117 - 231 = 46467445469 is a prime.

It is a super-2 number, since 2×486149291172 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (48614929417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24307464558 + 24307464559.

It is an arithmetic number, because the mean of its divisors is an integer number (24307464559).

Almost surely, 248614929117 is an apocalyptic number.

It is an amenable number.

48614929117 is a deficient number, since it is larger than the sum of its proper divisors (1).

48614929117 is an equidigital number, since it uses as much as digits as its factorization.

48614929117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 870912, while the sum is 52.

The spelling of 48614929117 in words is "forty-eight billion, six hundred fourteen million, nine hundred twenty-nine thousand, one hundred seventeen".