Base | Representation |
---|---|
bin | 100011100101101001011… |
… | …1101100000011101111111 |
3 | 122022121001222112022210220 |
4 | 1013023102331200131333 |
5 | 1120114200300400413 |
6 | 14222554122432423 |
7 | 1013243540025045 |
oct | 107132275403577 |
9 | 18277058468726 |
10 | 4891212121983 |
11 | 1616395802660 |
12 | 66bb49062713 |
13 | 296315a44205 |
14 | 12ca4356a395 |
15 | 87371c5b223 |
hex | 472d2f6077f |
4891212121983 has 32 divisors (see below), whose sum is σ = 7359921321984. Its totient is φ = 2862522960000.
The previous prime is 4891212121981. The next prime is 4891212122011. The reversal of 4891212121983 is 3891212121984.
It is a happy number.
It is not a de Polignac number, because 4891212121983 - 21 = 4891212121981 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4891212121981) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4714128 + ... + 5657333.
It is an arithmetic number, because the mean of its divisors is an integer number (229997541312).
Almost surely, 24891212121983 is an apocalyptic number.
4891212121983 is a deficient number, since it is larger than the sum of its proper divisors (2468709200001).
4891212121983 is a wasteful number, since it uses less digits than its factorization.
4891212121983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10371967.
The product of its digits is 497664, while the sum is 51.
Subtracting from 4891212121983 its reverse (3891212121984), we obtain a palindrome (999999999999).
The spelling of 4891212121983 in words is "four trillion, eight hundred ninety-one billion, two hundred twelve million, one hundred twenty-one thousand, nine hundred eighty-three".
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