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4891212121983 = 3113146110371461
BaseRepresentation
bin100011100101101001011…
…1101100000011101111111
3122022121001222112022210220
41013023102331200131333
51120114200300400413
614222554122432423
71013243540025045
oct107132275403577
918277058468726
104891212121983
111616395802660
1266bb49062713
13296315a44205
1412ca4356a395
1587371c5b223
hex472d2f6077f

4891212121983 has 32 divisors (see below), whose sum is σ = 7359921321984. Its totient is φ = 2862522960000.

The previous prime is 4891212121981. The next prime is 4891212122011. The reversal of 4891212121983 is 3891212121984.

It is a happy number.

It is not a de Polignac number, because 4891212121983 - 21 = 4891212121981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4891212121981) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4714128 + ... + 5657333.

It is an arithmetic number, because the mean of its divisors is an integer number (229997541312).

Almost surely, 24891212121983 is an apocalyptic number.

4891212121983 is a deficient number, since it is larger than the sum of its proper divisors (2468709200001).

4891212121983 is a wasteful number, since it uses less digits than its factorization.

4891212121983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10371967.

The product of its digits is 497664, while the sum is 51.

Subtracting from 4891212121983 its reverse (3891212121984), we obtain a palindrome (999999999999).

The spelling of 4891212121983 in words is "four trillion, eight hundred ninety-one billion, two hundred twelve million, one hundred twenty-one thousand, nine hundred eighty-three".

Divisors: 1 3 11 31 33 93 341 461 1023 1383 5071 14291 15213 42873 157201 471603 10371461 31114383 114086071 321515291 342258213 964545873 3536668201 4781243521 10610004603 14343730563 52593678731 148218549151 157781036193 444655647453 1630404040661 4891212121983