Base | Representation |
---|---|
bin | 101101100101100010… |
… | …001110100100001111 |
3 | 11200100021111201001101 |
4 | 231211202032210033 |
5 | 1300221204033011 |
6 | 34253023523531 |
7 | 3351660040546 |
oct | 554542164417 |
9 | 150307451041 |
10 | 48948111631 |
11 | 19838a29821 |
12 | 95a07595a7 |
13 | 4800b65a83 |
14 | 2524b5715d |
15 | 14173642c1 |
hex | b6588e90f |
48948111631 has 2 divisors, whose sum is σ = 48948111632. Its totient is φ = 48948111630.
The previous prime is 48948111623. The next prime is 48948111683. The reversal of 48948111631 is 13611184984.
48948111631 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48948111631 - 23 = 48948111623 is a prime.
It is a super-2 number, since 2×489481116312 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48948111431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24474055815 + 24474055816.
It is an arithmetic number, because the mean of its divisors is an integer number (24474055816).
Almost surely, 248948111631 is an apocalyptic number.
48948111631 is a deficient number, since it is larger than the sum of its proper divisors (1).
48948111631 is an equidigital number, since it uses as much as digits as its factorization.
48948111631 is an evil number, because the sum of its binary digits is even.
The product of its digits is 165888, while the sum is 46.
The spelling of 48948111631 in words is "forty-eight billion, nine hundred forty-eight million, one hundred eleven thousand, six hundred thirty-one".
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