Base | Representation |
---|---|
bin | 101101100101100010… |
… | …001110100101000011 |
3 | 11200100021111201010022 |
4 | 231211202032211003 |
5 | 1300221204033213 |
6 | 34253023524055 |
7 | 3351660040652 |
oct | 554542164503 |
9 | 150307451108 |
10 | 48948111683 |
11 | 19838a29869 |
12 | 95a075962b |
13 | 4800b65ac3 |
14 | 2524b57199 |
15 | 1417364308 |
hex | b6588e943 |
48948111683 has 2 divisors, whose sum is σ = 48948111684. Its totient is φ = 48948111682.
The previous prime is 48948111631. The next prime is 48948111689. The reversal of 48948111683 is 38611184984.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48948111683 - 230 = 47874369859 is a prime.
It is not a weakly prime, because it can be changed into another prime (48948111689) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24474055841 + 24474055842.
It is an arithmetic number, because the mean of its divisors is an integer number (24474055842).
Almost surely, 248948111683 is an apocalyptic number.
48948111683 is a deficient number, since it is larger than the sum of its proper divisors (1).
48948111683 is an equidigital number, since it uses as much as digits as its factorization.
48948111683 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1327104, while the sum is 53.
The spelling of 48948111683 in words is "forty-eight billion, nine hundred forty-eight million, one hundred eleven thousand, six hundred eighty-three".
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