Base | Representation |
---|---|
bin | 101101101001001110… |
… | …010110100000100111 |
3 | 11200111120222110212011 |
4 | 231221032112200213 |
5 | 1300333030311101 |
6 | 34303114335051 |
7 | 3353341132654 |
oct | 555116264047 |
9 | 150446873764 |
10 | 49010010151 |
11 | 1986a967023 |
12 | 95b942a487 |
13 | 4810928c0b |
14 | 252d06ac2b |
15 | 141c9de751 |
hex | b69396827 |
49010010151 has 2 divisors, whose sum is σ = 49010010152. Its totient is φ = 49010010150.
The previous prime is 49010010149. The next prime is 49010010157. The reversal of 49010010151 is 15101001094.
49010010151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49010010151 - 21 = 49010010149 is a prime.
It is a super-2 number, since 2×490100101512 (a number of 22 digits) contains 22 as substring.
Together with 49010010149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49010010157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24505005075 + 24505005076.
It is an arithmetic number, because the mean of its divisors is an integer number (24505005076).
Almost surely, 249010010151 is an apocalyptic number.
49010010151 is a deficient number, since it is larger than the sum of its proper divisors (1).
49010010151 is an equidigital number, since it uses as much as digits as its factorization.
49010010151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 22.
The spelling of 49010010151 in words is "forty-nine billion, ten million, ten thousand, one hundred fifty-one".
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